The constant R in the ideal gas equation of state may have different values according to the unit system in use. For example
R | Units |
---|---|
SI units | |
8.314 | J\,K^{−1}\,mol^{−1} |
8.314 | m^3\,Pa\,K^{−1}\,mol^{−1} |
8.314 | kg\,m^2\,s^{-2}\,K^{−1}\,mol^{−1} |
Other units | |
8314.462 | L\,Pa\,K^{−1}\,mol^{−1} |
8.314 | L\,kPa\,K^{−1}\,mol^{−1} |
8.314\times10^{-2} | L\,bar\,K^{−1}\,mol^{−1} |
8.314\times10^{7} | erg\,K^{−1}\,mol^{−1} |
7.302\times10^{-1} | atm\,ft^3\,lb_{mol}^{−1}\,R^{−1} |
10.731 | psi\,ft^3\,lb_{mol}^{−1}\,R^{−1} |
1.986 | BTU\,lb_{mol}^{−1}\,R^{−1} |
297.031 | inH_2O\,ft^3\,lb_{mol}^{−1}\,R^{−1} |
554.984 | torr\,ft^3\,lb_{mol}^{−1}\,R^{−1} |
8.206\times10^{-2} | L\,atm\,K^{−1}\,mol^{−1} |
62.363 | L\,torr\,K^{−1}\,mol^{−1} |
1.987 | cal\,K^{−1}\,mol^{−1} |
8.206\times10^{-5} | m^3\,atm\,K^{−1}\,mol^{−1} |
However, as you may imagine if a gas in question has an idealized behavior then the constant R may apply. A gas behaves as an ideal gas under certain conditions of pressure, P=0, and temperature so that the following equation of state applies
PV=nRT
One way to check for the constant R for any given gas is in a plot of PV/nT versus P which should be a straight line. Also, when this line cuts the vertical axis (PV/nT) at P=0 you should read any of the values of the table above (according to the units you were using).
Other stuff of interest
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- What is an Equation of State
- Minor losses - Formulas
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- What are the most important process variables?
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Ildebrando.
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